Stats/Math Problems and Riddles #2

:hmmyes:

Here is my answer to the other question

Expected number: sum(totalchildren*probability)

Gender ratio:

1/(sum(totalchildren-1*probability))

64 couples.

First birth. 32 girls, 32 boys. 32-32
Second birth. 16 girls, 16 boys. 48-48
Third birth. 8 girls, 8 boys. 56-56
Fourth birth. 4 girls, 4 boys. 60-60
Fifth birth. 2 girls, 2 boys. 62-62
Sixth birth. 1 girl, 1 boy. 63-63

It's always the same. Similar to Zeno's paradox.

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i guess that makes the expected number of children / couple 2

The results may vary. In India, they test for gender, and abort the girls, because of the dowry.

Here are the rest of the problems for those that are curious:

wow yeah I hATE probability and statistics

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8X82dSg

  1. sum two die rolls, mask to 3 bits. reroll on 000.
  1. take the first bit of stream_cipher(random_key, coin_flips).
  1. 33%

i don't know how to do four off the top fo my head.

i kinda missed the ship on this but this throws me back to stats class <3 i miss math

the last math class i took was algebra 2 and i got a 61% (pass). i'm SO bad at math

anyways im sure the meme answer to #3 is

implying theres a gender binary

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just kidding i took one in junior college and failed that

@ironstove do we know the distribution of heads to tails for the weighted coin or is it arbitrary?

generate source of randomness -> xor it with weigthed coin outcome.