Here is my answer to the other question
Expected number: sum(totalchildren*probability)
Gender ratio:
1/(sum(totalchildren-1*probability))
64 couples.
First birth. 32 girls, 32 boys. 32-32
Second birth. 16 girls, 16 boys. 48-48
Third birth. 8 girls, 8 boys. 56-56
Fourth birth. 4 girls, 4 boys. 60-60
Fifth birth. 2 girls, 2 boys. 62-62
Sixth birth. 1 girl, 1 boy. 63-63
It's always the same. Similar to Zeno's paradox.
1 Like
iaafr
65
i guess that makes the expected number of children / couple 2
The results may vary. In India, they test for gender, and abort the girls, because of the dowry.
Here are the rest of the problems for those that are curious:
a2pas
68
wow yeah I hATE probability and statistics
jones
74
i don't know how to do four off the top fo my head.
Friend
75
i kinda missed the ship on this but this throws me back to stats class <3 i miss math
the last math class i took was algebra 2 and i got a 61% (pass). i'm SO bad at math
Friend
77
anyways im sure the meme answer to #3 is
implying theres a gender binary
1 Like
just kidding i took one in junior college and failed that
Friend
79
@ironstove do we know the distribution of heads to tails for the weighted coin or is it arbitrary?
jones
80
generate source of randomness -> xor it with weigthed coin outcome.