Stats/Math Problems and Riddles #2

im laughing as im typing this but im not trolling

lol. i guess it can be reworded to - what is your chance of successfully guessing if they have 2 girls or not

Question 2 explanation @wolfy @iaafr

yea i already went over ur conception here and why it doesnt matter for my understanding of the problem

B/G and G/B aren't different you fucking american burger

if you have 2 kids. one in the kitchen. the other in the living room. you tell them to switch places. do you now have 2 brand new children?

You don't understand basic logic

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Just look at the picture - I drew it out because I figured it would help you to see images instead of reading words

STOP TROLLING MEEEEE RAAAAAAAAAAAAAAAAAAAAAAAA

The two kids each represent different possibilities - as shown in the chart

There is

one 25% chance of kid 1 being a boy and kid 2 being a girl
one 25% chance of kid 1 being a girl and kid 2 being a boy

as you will see if you actually map it out

Therefore after 1 possibility is eliminated, you have 3 equally likely possibilities [BG, GB, GG] with therefore a 33% chance of GG

if first kid is named A
second kid is named B

if A=girl and B=boy

is different than A=boy and B=girl, then

u also have to count

A=girl and B=girl

is different to B=girl and A=girl

following your mongoloid logic

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You're wrong because we wouldn't name our kids A and B.

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Can you just look at the picture

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A: (b50%) (g50%)
B: (b50%) (g50%)

Chance AbBb: 25%
Chance AbBg: 25%
Chance AgBb: 25%
Chance AgBg: 25%

I am wasting my time on this when I could be making a picture of the other question

if you did not know anything about the couple's childrne

u just know that they have 2 child

then YES, there's 25% chance for both girls, 25% chance for both boys, and 50% chance for boy/girl

but thats not how randomness works

you ALREADY KNOW that one of them is a girl. there is no randomness, there is no coinflip. it changes the math. there's only 1 flip - the second child

this is basically gambler's fallacy

if u flip a coin 9 times and it flips head every time, on the 10th flip, is it more likely to flip head or tails?

you might say tails, because "what's the chance of 10 consecutive heads? thats unliekly!" and thats true when you look at all of the 10 flips as a stream of continuity.

but those 9 consecutive flips ALREADY HAPPENED. THEY ARE THERE. so the 10th flip will be 50/50 regardless of what happened before.

at that moment, when you KNOW the 9 previous lfips were heads - it doesn't matter. just like how it doesn't matter that one of the children is a girl - you're just flipping a coin for the unknown one

in conclusion:

chance for 10 consecutive head coin flips : extremely low

chance for a 10th consecutive head lfip after 9 already done head flips: 50/50

do you udnerstand??

They didn't say we have 1 girl what's the chance the next will be a girl

They said we have 2 children, at least 1 of which is a girl, what's the chance both are girls

both of those are the same

it doesn't matter which one is older and which one is younger

the moment u know 1 is a girl, she is taken out of the equation

We have 2 children:

Chance AbBb: 25%
Chance AbBg: 25%
Chance AgBb: 25%
Chance AgBg: 25%

At least 1 of which is a girl:

Chance AbBb: 25%
Chance AbBg: 25% 33%
Chance AgBb: 25% 33%
Chance AgBg: 25% 33%

What is the chance both are girls:

Chance AgBg: 25% 33%

A couple has 100 children

At least 99 of them are girls

What is the chance 100 of them are girls?

50% or 1%?

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well it wont be 1% it might be something slightly different but close to 1% by your math but you get the point